We have the quadratic in standard form y = ax² + bx + c with a = −47/5, b = 0, c = −1.
- Find x-coordinate of the vertex using x = −b/(2a):
x = −0 / (2·(−47/5)) = 0. - Find y-coordinate by evaluating at x = 0:
y = (−47/5)·0² − 1 = −1.
Vertex: (0, −1)
Step-by-step solution to find the vertex of the parabola y = −(47/5)x² − 1. Uses the vertex formula x = −b/(2a) for a quadratic in standard form and evaluates coordinates exactly.
We have the quadratic in standard form y = ax² + bx + c with a = −47/5, b = 0, c = −1.
Vertex: (0, −1)
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