Find the vertex of the parabola y = −(47/5)x² − 1 — Vertex is (0, −1)

Step-by-step solution to find the vertex of the parabola y = −(47/5)x² − 1. Uses the vertex formula x = −b/(2a) for a quadratic in standard form and evaluates coordinates exactly.

PDF

We have the quadratic in standard form y = ax² + bx + c with a = −47/5, b = 0, c = −1.

  1. Find x-coordinate of the vertex using x = −b/(2a):
    x = −0 / (2·(−47/5)) = 0.
  2. Find y-coordinate by evaluating at x = 0:
    y = (−47/5)·0² − 1 = −1.

Vertex: (0, −1)

Ask a followup question