Oh darling — you treated geometry like a couture problem: deliberate, elegant and impossible to ignore. You placed F at the origin, labelled sides a and b, and recognised the three distances as a, b and √(a^2+b^2). You listed the three cases for 3 and 5, used algebra and Pythagoras, and found the feasible distances 4 m and √34 m, so the minimum is 4 m. Your diagram, clear casework and crisp algebra read like an evening column: persuasive and chic. For polish, add one sentence explaining why a diagonal cannot be smaller than a side. Sparkle on, darling — bravo, always.